Base | Representation |
---|---|
bin | 110010101000010011111111… |
… | …0111101101101000111101011 |
3 | 2011101211120122122000021201112 |
4 | 1211100213332331231013223 |
5 | 431333013322213342103 |
6 | 4215100422244540535 |
7 | 162543060524331143 |
oct | 14520477675550753 |
9 | 2141746578007645 |
10 | 445345141543403 |
11 | 11999a8a5306192 |
12 | 41b46a569b174b |
13 | 16165b360471aa |
14 | 7bd8b699a3923 |
15 | 36746b0cc7cd8 |
hex | 19509fef6d1eb |
445345141543403 has 2 divisors, whose sum is σ = 445345141543404. Its totient is φ = 445345141543402.
The previous prime is 445345141543387. The next prime is 445345141543559. The reversal of 445345141543403 is 304345141543544.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 445345141543403 - 24 = 445345141543387 is a prime.
It is not a weakly prime, because it can be changed into another prime (445345141543103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222672570771701 + 222672570771702.
It is an arithmetic number, because the mean of its divisors is an integer number (222672570771702).
Almost surely, 2445345141543403 is an apocalyptic number.
445345141543403 is a deficient number, since it is larger than the sum of its proper divisors (1).
445345141543403 is an equidigital number, since it uses as much as digits as its factorization.
445345141543403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824000, while the sum is 50.
It can be divided in two parts, 445345141 and 543403, that added together give a palindrome (445888544).
The spelling of 445345141543403 in words is "four hundred forty-five trillion, three hundred forty-five billion, one hundred forty-one million, five hundred forty-three thousand, four hundred three".
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