4500113 has 4 divisors (see below), whose sum is σ = 4504500. Its totient is φ = 4495728.

The previous prime is 4500103. The next prime is 4500127. The reversal of 4500113 is 3110054.

4500113 is nontrivially palindromic in base 2.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3110054 = 2 ⋅1555027.

It can be written as a sum of positive squares in 2 ways, for example, as 305809 + 4194304 = 553^2 + 2048^2 .

It is a cyclic number.

It is not a de Polignac number, because 4500113 - 2⁶ = 4500049 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4500103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263 + ... + 3011.

It is an arithmetic number, because the mean of its divisors is an integer number (1126125).

Almost surely, 2^4500113 is an apocalyptic number.

It is an amenable number.

4500113 is a deficient number, since it is larger than the sum of its proper divisors (4387).

4500113 is a wasteful number, since it uses less digits than its factorization.

4500113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4386.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 4500113 is about 2121.3469777479. The cubic root of 4500113 is about 165.0977443509.

Adding to 4500113 its reverse (3110054), we get a palindrome (7610167).

The spelling of 4500113 in words is "four million, five hundred thousand, one hundred thirteen".