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450142345450121 is a prime number
BaseRepresentation
bin110011001011001101110111…
…0100110010101001010001001
32012000211012002000111110201212
41212112123232212111022021
5433000113010413400441
64233212312205222505
7163546465644621662
oct14626335646251211
92160735060443655
10450142345450121
1112047a329902255
12425a0728861a35
131642331972c30c
147d23011b80369
15370937e85ceeb
hex19966ee995289

450142345450121 has 2 divisors, whose sum is σ = 450142345450122. Its totient is φ = 450142345450120.

The previous prime is 450142345450073. The next prime is 450142345450157. The reversal of 450142345450121 is 121054543241054.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 447554545585225 + 2587799864896 = 21155485^2 + 1608664^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-450142345450121 is a prime.

It is not a weakly prime, because it can be changed into another prime (450142345450181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225071172725060 + 225071172725061.

It is an arithmetic number, because the mean of its divisors is an integer number (225071172725061).

Almost surely, 2450142345450121 is an apocalyptic number.

It is an amenable number.

450142345450121 is a deficient number, since it is larger than the sum of its proper divisors (1).

450142345450121 is an equidigital number, since it uses as much as digits as its factorization.

450142345450121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384000, while the sum is 41.

Adding to 450142345450121 its reverse (121054543241054), we get a palindrome (571196888691175).

The spelling of 450142345450121 in words is "four hundred fifty trillion, one hundred forty-two billion, three hundred forty-five million, four hundred fifty thousand, one hundred twenty-one".