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450161041435331 is a prime number
BaseRepresentation
bin110011001011010110100100…
…0111101110110101011000011
32012000212222022222021220222112
41212112231020331312223003
5433000414303101412311
64233225043313125535
7163551030154104332
oct14626551075665303
92160788288256875
10450161041435331
111204872532416a6
12425a4285b598ab
1316425008bc4765
147d23ca6bbbd19
153709ac5d9428b
hex1996b48f76ac3

450161041435331 has 2 divisors, whose sum is σ = 450161041435332. Its totient is φ = 450161041435330.

The previous prime is 450161041435321. The next prime is 450161041435373. The reversal of 450161041435331 is 133534140161054.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 450161041435331 - 218 = 450161041173187 is a prime.

It is a super-2 number, since 2×4501610414353312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (450161041435321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225080520717665 + 225080520717666.

It is an arithmetic number, because the mean of its divisors is an integer number (225080520717666).

Almost surely, 2450161041435331 is an apocalyptic number.

450161041435331 is a deficient number, since it is larger than the sum of its proper divisors (1).

450161041435331 is an equidigital number, since it uses as much as digits as its factorization.

450161041435331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 41.

Adding to 450161041435331 its reverse (133534140161054), we get a palindrome (583695181596385).

The spelling of 450161041435331 in words is "four hundred fifty trillion, one hundred sixty-one billion, forty-one million, four hundred thirty-five thousand, three hundred thirty-one".