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450212543041 is a prime number
BaseRepresentation
bin1101000110100101100…
…00100011101001000001
31121001002002022211212011
412203102300203221001
524334013402334131
6542454053132521
744345454321532
oct6432260435101
91531062284764
10450212543041
11163a30275158
127330732a141
13335bb437581
1417b0cc1c689
15ba9ec740b1
hex68d2c23a41

450212543041 has 2 divisors, whose sum is σ = 450212543042. Its totient is φ = 450212543040.

The previous prime is 450212543009. The next prime is 450212543047. The reversal of 450212543041 is 140345212054.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 430494766641 + 19717776400 = 656121^2 + 140420^2 .

It is a cyclic number.

It is not a de Polignac number, because 450212543041 - 25 = 450212543009 is a prime.

It is a super-2 number, since 2×4502125430412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 450212542994 and 450212543012.

It is not a weakly prime, because it can be changed into another prime (450212543047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225106271520 + 225106271521.

It is an arithmetic number, because the mean of its divisors is an integer number (225106271521).

Almost surely, 2450212543041 is an apocalyptic number.

It is an amenable number.

450212543041 is a deficient number, since it is larger than the sum of its proper divisors (1).

450212543041 is an equidigital number, since it uses as much as digits as its factorization.

450212543041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 450212543041 its reverse (140345212054), we get a palindrome (590557755095).

The spelling of 450212543041 in words is "four hundred fifty billion, two hundred twelve million, five hundred forty-three thousand, forty-one".