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451114121 is a prime number
BaseRepresentation
bin11010111000110…
…111010010001001
31011102211222020102
4122320313102021
51410441122441
6112432535145
714115256343
oct3270672211
91142758212
10451114121
11211707797
121070b14b5
13725c9b43
1443cac293
152990d69b
hex1ae37489

451114121 has 2 divisors, whose sum is σ = 451114122. Its totient is φ = 451114120.

The previous prime is 451114109. The next prime is 451114127. The reversal of 451114121 is 121411154.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 427455625 + 23658496 = 20675^2 + 4864^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-451114121 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 451114093 and 451114102.

It is not a weakly prime, because it can be changed into another prime (451114127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225557060 + 225557061.

It is an arithmetic number, because the mean of its divisors is an integer number (225557061).

Almost surely, 2451114121 is an apocalyptic number.

It is an amenable number.

451114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

451114121 is an equidigital number, since it uses as much as digits as its factorization.

451114121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 160, while the sum is 20.

The square root of 451114121 is about 21239.4472856522. The cubic root of 451114121 is about 766.9413270683.

Adding to 451114121 its reverse (121411154), we get a palindrome (572525275).

The spelling of 451114121 in words is "four hundred fifty-one million, one hundred fourteen thousand, one hundred twenty-one".