Base | Representation |
---|---|
bin | 100000110100110000011… |
… | …1101001110011010001111 |
3 | 120222021120012111010202102 |
4 | 1001221200331032122033 |
5 | 1042403212113321333 |
6 | 13332252042345315 |
7 | 643635161020532 |
oct | 101514075163217 |
9 | 16867505433672 |
10 | 4511342323343 |
11 | 148a282149509 |
12 | 60a3b34bb23b |
13 | 269557a69b2b |
14 | 1184c8aa2a19 |
15 | 7c53c74bae8 |
hex | 41a60f4e68f |
4511342323343 has 4 divisors (see below), whose sum is σ = 4511388255240. Its totient is φ = 4511296391448.
The previous prime is 4511342323309. The next prime is 4511342323381. The reversal of 4511342323343 is 3433232431154.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4511342323343 - 28 = 4511342323087 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4511342323297 and 4511342323306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4511342323043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22818305 + ... + 23015162.
It is an arithmetic number, because the mean of its divisors is an integer number (1127847063810).
Almost surely, 24511342323343 is an apocalyptic number.
4511342323343 is a deficient number, since it is larger than the sum of its proper divisors (45931897).
4511342323343 is an equidigital number, since it uses as much as digits as its factorization.
4511342323343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45931896.
The product of its digits is 311040, while the sum is 38.
Adding to 4511342323343 its reverse (3433232431154), we get a palindrome (7944574754497).
The spelling of 4511342323343 in words is "four trillion, five hundred eleven billion, three hundred forty-two million, three hundred twenty-three thousand, three hundred forty-three".
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