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4512020131 is a prime number
BaseRepresentation
bin1000011001110111…
…11111011010100011
3102122110011101000201
410030323333122203
533220034121011
62023420130031
7216545352433
oct41473773243
912573141021
104512020131
111a05a10563
12a5b096917
1356ba249c8
1430b3582c3
151b61b4cc1
hex10ceff6a3

4512020131 has 2 divisors, whose sum is σ = 4512020132. Its totient is φ = 4512020130.

The previous prime is 4512020077. The next prime is 4512020189. The reversal of 4512020131 is 1310202154.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4512020131 - 211 = 4512018083 is a prime.

It is a super-2 number, since 2×45120201312 = 40716651325098514322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4512020099 and 4512020108.

It is not a weakly prime, because it can be changed into another prime (4512020431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2256010065 + 2256010066.

It is an arithmetic number, because the mean of its divisors is an integer number (2256010066).

Almost surely, 24512020131 is an apocalyptic number.

4512020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4512020131 is an equidigital number, since it uses as much as digits as its factorization.

4512020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 4512020131 is about 67171.5723427701. The cubic root of 4512020131 is about 1652.4323026549.

Adding to 4512020131 its reverse (1310202154), we get a palindrome (5822222285).

The spelling of 4512020131 in words is "four billion, five hundred twelve million, twenty thousand, one hundred thirty-one".