Base | Representation |
---|---|
bin | 110011010011101110101001… |
… | …0000000010111011100100011 |
3 | 2012011222000210021121221120011 |
4 | 1212213131102000113130203 |
5 | 433123244434021333011 |
6 | 4235505552142225351 |
7 | 164030143065154141 |
oct | 14647352200273443 |
9 | 2164860707557504 |
10 | 451312244324131 |
11 | 1208904a2264913 |
12 | 4274b405585257 |
13 | 164a973ca05a68 |
14 | 7d638b4658591 |
15 | 3729a01ae6621 |
hex | 19a7752017723 |
451312244324131 has 2 divisors, whose sum is σ = 451312244324132. Its totient is φ = 451312244324130.
The previous prime is 451312244324111. The next prime is 451312244324177. The reversal of 451312244324131 is 131423442213154.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 451312244324131 - 211 = 451312244322083 is a prime.
It is a super-2 number, since 2×4513122443241312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (451312244324111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225656122162065 + 225656122162066.
It is an arithmetic number, because the mean of its divisors is an integer number (225656122162066).
Almost surely, 2451312244324131 is an apocalyptic number.
451312244324131 is a deficient number, since it is larger than the sum of its proper divisors (1).
451312244324131 is an equidigital number, since it uses as much as digits as its factorization.
451312244324131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 276480, while the sum is 40.
Adding to 451312244324131 its reverse (131423442213154), we get a palindrome (582735686537285).
The spelling of 451312244324131 in words is "four hundred fifty-one trillion, three hundred twelve billion, two hundred forty-four million, three hundred twenty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •