Base | Representation |
---|---|
bin | 101010000011010101… |
… | …100001111001010001 |
3 | 11022112210120202211102 |
4 | 222003111201321101 |
5 | 1214433200211423 |
6 | 32424300154145 |
7 | 3155636201405 |
oct | 520325417121 |
9 | 138483522742 |
10 | 45153132113 |
11 | 18170847511 |
12 | 8901838955 |
13 | 434786886b |
14 | 2284b31105 |
15 | 12940dac28 |
hex | a83561e51 |
45153132113 has 2 divisors, whose sum is σ = 45153132114. Its totient is φ = 45153132112.
The previous prime is 45153132091. The next prime is 45153132139. The reversal of 45153132113 is 31123135154.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28020416449 + 17132715664 = 167393^2 + 130892^2 .
It is a cyclic number.
It is not a de Polignac number, because 45153132113 - 216 = 45153066577 is a prime.
It is a super-2 number, since 2×451531321132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (45153132173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22576566056 + 22576566057.
It is an arithmetic number, because the mean of its divisors is an integer number (22576566057).
Almost surely, 245153132113 is an apocalyptic number.
It is an amenable number.
45153132113 is a deficient number, since it is larger than the sum of its proper divisors (1).
45153132113 is an equidigital number, since it uses as much as digits as its factorization.
45153132113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
Adding to 45153132113 its reverse (31123135154), we get a palindrome (76276267267).
The spelling of 45153132113 in words is "forty-five billion, one hundred fifty-three million, one hundred thirty-two thousand, one hundred thirteen".
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