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454031233514081 is a prime number
BaseRepresentation
bin110011100111100000110001…
…0011000111111101001100001
32012112120221222022110222210122
41213033001202120333221201
5434002321431234422311
64245351022541010025
7164430450140016446
oct14717014230775141
92175527868428718
10454031233514081
11121739623826803
1242b0a365553915
1316645c6685b322
14801932c3719cd
1537755daccd0db
hex19cf06263fa61

454031233514081 has 2 divisors, whose sum is σ = 454031233514082. Its totient is φ = 454031233514080.

The previous prime is 454031233514057. The next prime is 454031233514191. The reversal of 454031233514081 is 180415332130454.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 440174666515600 + 13856566998481 = 20980340^2 + 3722441^2 .

It is a cyclic number.

It is not a de Polignac number, because 454031233514081 - 214 = 454031233497697 is a prime.

It is a super-2 number, since 2×4540312335140812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (454031233514281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 227015616757040 + 227015616757041.

It is an arithmetic number, because the mean of its divisors is an integer number (227015616757041).

Almost surely, 2454031233514081 is an apocalyptic number.

It is an amenable number.

454031233514081 is a deficient number, since it is larger than the sum of its proper divisors (1).

454031233514081 is an equidigital number, since it uses as much as digits as its factorization.

454031233514081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 44.

The spelling of 454031233514081 in words is "four hundred fifty-four trillion, thirty-one billion, two hundred thirty-three million, five hundred fourteen thousand, eighty-one".