Base | Representation |
---|---|
bin | 10100101010010001110011… |
… | …01001111100100001011011 |
3 | 12221212100212001002200112012 |
4 | 22111020321221330201123 |
5 | 21423334023111313303 |
6 | 240343405320540135 |
7 | 12366302230422245 |
oct | 1225107151744133 |
9 | 187770761080465 |
10 | 45433131354203 |
11 | 135270a023479a |
12 | 51192b392164b |
13 | 1c47431017658 |
14 | b30d922a9095 |
15 | 53bc477ee5d8 |
hex | 295239a7c85b |
45433131354203 has 2 divisors, whose sum is σ = 45433131354204. Its totient is φ = 45433131354202.
The previous prime is 45433131354181. The next prime is 45433131354223. The reversal of 45433131354203 is 30245313133454.
45433131354203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 45433131354203 - 222 = 45433127159899 is a prime.
It is not a weakly prime, because it can be changed into another prime (45433131354223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22716565677101 + 22716565677102.
It is an arithmetic number, because the mean of its divisors is an integer number (22716565677102).
Almost surely, 245433131354203 is an apocalyptic number.
45433131354203 is a deficient number, since it is larger than the sum of its proper divisors (1).
45433131354203 is an equidigital number, since it uses as much as digits as its factorization.
45433131354203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 45433131354203 its reverse (30245313133454), we get a palindrome (75678444487657).
The spelling of 45433131354203 in words is "forty-five trillion, four hundred thirty-three billion, one hundred thirty-one million, three hundred fifty-four thousand, two hundred three".
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