Base | Representation |
---|---|
bin | 10100101100111010001001… |
… | …10001100011010000000001 |
3 | 12222012000010211121220011211 |
4 | 22112131010301203100001 |
5 | 21431324123111213213 |
6 | 240453113544210121 |
7 | 12405652033135645 |
oct | 1226350461432001 |
9 | 188160124556154 |
10 | 45523512210433 |
11 | 1356145a9357a4 |
12 | 5132918169941 |
13 | 1c52b05a0773a |
14 | b354c79c6c25 |
15 | 53e28730c53d |
hex | 296744c63401 |
45523512210433 has 2 divisors, whose sum is σ = 45523512210434. Its totient is φ = 45523512210432.
The previous prime is 45523512210403. The next prime is 45523512210439. The reversal of 45523512210433 is 33401221532554.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44957869833969 + 565642376464 = 6705063^2 + 752092^2 .
It is a cyclic number.
It is not a de Polignac number, because 45523512210433 - 213 = 45523512202241 is a prime.
It is not a weakly prime, because it can be changed into another prime (45523512210439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22761756105216 + 22761756105217.
It is an arithmetic number, because the mean of its divisors is an integer number (22761756105217).
Almost surely, 245523512210433 is an apocalyptic number.
It is an amenable number.
45523512210433 is a deficient number, since it is larger than the sum of its proper divisors (1).
45523512210433 is an equidigital number, since it uses as much as digits as its factorization.
45523512210433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 45523512210433 its reverse (33401221532554), we get a palindrome (78924733742987).
The spelling of 45523512210433 in words is "forty-five trillion, five hundred twenty-three billion, five hundred twelve million, two hundred ten thousand, four hundred thirty-three".
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