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4553132153497 is a prime number
BaseRepresentation
bin100001001000001101111…
…0100110001101010011001
3121010021102121102110122121
41002100123310301222121
51044044303312402442
613403402515421241
7646644600511204
oct102203364615231
917107377373577
104553132153497
1114a5a77445424
126165168b4821
1327048788b495
1411a530c5a93b
157d68642d967
hex4241bd31a99

4553132153497 has 2 divisors, whose sum is σ = 4553132153498. Its totient is φ = 4553132153496.

The previous prime is 4553132153477. The next prime is 4553132153513. The reversal of 4553132153497 is 7943512313554.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4547859070041 + 5273083456 = 2132571^2 + 72616^2 .

It is a cyclic number.

It is not a de Polignac number, because 4553132153497 - 27 = 4553132153369 is a prime.

It is not a weakly prime, because it can be changed into another prime (4553132153477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2276566076748 + 2276566076749.

It is an arithmetic number, because the mean of its divisors is an integer number (2276566076749).

Almost surely, 24553132153497 is an apocalyptic number.

It is an amenable number.

4553132153497 is a deficient number, since it is larger than the sum of its proper divisors (1).

4553132153497 is an equidigital number, since it uses as much as digits as its factorization.

4553132153497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6804000, while the sum is 52.

The spelling of 4553132153497 in words is "four trillion, five hundred fifty-three billion, one hundred thirty-two million, one hundred fifty-three thousand, four hundred ninety-seven".