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4555160248273 is a prime number
BaseRepresentation
bin100001001001001010010…
…1101010101111111010001
3121010110122221122100122221
41002102110231111333101
51044112432010421043
613404340044501041
7650046055155025
oct102222455257721
917113587570587
104555160248273
1114a6918231008
126169a1b4a781
1327071bac156b
1411a68434a385
157d7544e08ed
hex42494b55fd1

4555160248273 has 2 divisors, whose sum is σ = 4555160248274. Its totient is φ = 4555160248272.

The previous prime is 4555160248241. The next prime is 4555160248319. The reversal of 4555160248273 is 3728420615554.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2701578747904 + 1853581500369 = 1643648^2 + 1361463^2 .

It is a cyclic number.

It is not a de Polignac number, because 4555160248273 - 25 = 4555160248241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4555160248273.

It is not a weakly prime, because it can be changed into another prime (4555160242273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2277580124136 + 2277580124137.

It is an arithmetic number, because the mean of its divisors is an integer number (2277580124137).

Almost surely, 24555160248273 is an apocalyptic number.

It is an amenable number.

4555160248273 is a deficient number, since it is larger than the sum of its proper divisors (1).

4555160248273 is an equidigital number, since it uses as much as digits as its factorization.

4555160248273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064000, while the sum is 52.

The spelling of 4555160248273 in words is "four trillion, five hundred fifty-five billion, one hundred sixty million, two hundred forty-eight thousand, two hundred seventy-three".