Base | Representation |
---|---|
bin | 101010110101011101… |
… | …010100010101001011 |
3 | 11101201101220001001112 |
4 | 222311131110111023 |
5 | 1223143433101012 |
6 | 33043535440535 |
7 | 3215526562031 |
oct | 526535242513 |
9 | 141641801045 |
10 | 45994034507 |
11 | 18562484973 |
12 | 8ab738614b |
13 | 444cb3cc45 |
14 | 23246a6551 |
15 | 12e2d42122 |
hex | ab575454b |
45994034507 has 2 divisors, whose sum is σ = 45994034508. Its totient is φ = 45994034506.
The previous prime is 45994034453. The next prime is 45994034519. The reversal of 45994034507 is 70543049954.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 45994034507 - 210 = 45994033483 is a prime.
It is a super-3 number, since 3×459940345073 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (45994034707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22997017253 + 22997017254.
It is an arithmetic number, because the mean of its divisors is an integer number (22997017254).
Almost surely, 245994034507 is an apocalyptic number.
45994034507 is a deficient number, since it is larger than the sum of its proper divisors (1).
45994034507 is an equidigital number, since it uses as much as digits as its factorization.
45994034507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2721600, while the sum is 50.
The spelling of 45994034507 in words is "forty-five billion, nine hundred ninety-four million, thirty-four thousand, five hundred seven".
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