Base | Representation |
---|---|
bin | 100001100110000000110… |
… | …1001000100010110000001 |
3 | 121100101120211221001210211 |
4 | 1003030001221010112001 |
5 | 1101121324022323423 |
6 | 13453024025154121 |
7 | 654401321145661 |
oct | 103140151042601 |
9 | 17311524831724 |
10 | 4617117386113 |
11 | 152012143a761 |
12 | 6269b332b941 |
13 | 276513b6957b |
14 | 11d680adc1a1 |
15 | 8017d98b10d |
hex | 43301a44581 |
4617117386113 has 2 divisors, whose sum is σ = 4617117386114. Its totient is φ = 4617117386112.
The previous prime is 4617117386107. The next prime is 4617117386129. The reversal of 4617117386113 is 3116837117164.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3721457675664 + 895659710449 = 1929108^2 + 946393^2 .
It is a cyclic number.
It is not a de Polignac number, because 4617117386113 - 213 = 4617117377921 is a prime.
It is not a weakly prime, because it can be changed into another prime (4617117386153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2308558693056 + 2308558693057.
It is an arithmetic number, because the mean of its divisors is an integer number (2308558693057).
Almost surely, 24617117386113 is an apocalyptic number.
It is an amenable number.
4617117386113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4617117386113 is an equidigital number, since it uses as much as digits as its factorization.
4617117386113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 508032, while the sum is 49.
The spelling of 4617117386113 in words is "four trillion, six hundred seventeen billion, one hundred seventeen million, three hundred eighty-six thousand, one hundred thirteen".
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