Base | Representation |
---|---|
bin | 1101100011011001010… |
… | …00010101101100001101 |
3 | 1122111222222011100101001 |
4 | 12301230220111230031 |
5 | 30112202304410101 |
6 | 553532512420301 |
7 | 45433650015160 |
oct | 6615450255415 |
9 | 1574888140331 |
10 | 465678981901 |
11 | 16a547710631 |
12 | 76302b47691 |
13 | 34bb47b7843 |
14 | 18778d7dad7 |
15 | c1a79c2901 |
hex | 6c6ca15b0d |
465678981901 has 4 divisors (see below), whose sum is σ = 532204550752. Its totient is φ = 399153413052.
The previous prime is 465678981893. The next prime is 465678981953. The reversal of 465678981901 is 109189876564.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 465678981901 - 23 = 465678981893 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (465678981601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33262784415 + ... + 33262784428.
It is an arithmetic number, because the mean of its divisors is an integer number (133051137688).
Almost surely, 2465678981901 is an apocalyptic number.
It is an amenable number.
465678981901 is a deficient number, since it is larger than the sum of its proper divisors (66525568851).
465678981901 is an equidigital number, since it uses as much as digits as its factorization.
465678981901 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66525568850.
The product of its (nonzero) digits is 26127360, while the sum is 64.
The spelling of 465678981901 in words is "four hundred sixty-five billion, six hundred seventy-eight million, nine hundred eighty-one thousand, nine hundred one".
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