Base | Representation |
---|---|
bin | 1101101011010101010… |
… | …11010111101100111001 |
3 | 1122221000000020220221021 |
4 | 12311222223113230321 |
5 | 30144414421030213 |
6 | 555515450342441 |
7 | 45644403126202 |
oct | 6655253275471 |
9 | 1587000226837 |
10 | 469941189433 |
11 | 1713346061a1 |
12 | 770b242aa21 |
13 | 35413834231 |
14 | 18a6106a5a9 |
15 | c356c8dd8d |
hex | 6d6aad7b39 |
469941189433 has 2 divisors, whose sum is σ = 469941189434. Its totient is φ = 469941189432.
The previous prime is 469941189413. The next prime is 469941189439. The reversal of 469941189433 is 334981149964.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 272283588864 + 197657600569 = 521808^2 + 444587^2 .
It is a cyclic number.
It is not a de Polignac number, because 469941189433 - 217 = 469941058361 is a prime.
It is a super-2 number, since 2×4699411894332 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (469941189439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 234970594716 + 234970594717.
It is an arithmetic number, because the mean of its divisors is an integer number (234970594717).
Almost surely, 2469941189433 is an apocalyptic number.
It is an amenable number.
469941189433 is a deficient number, since it is larger than the sum of its proper divisors (1).
469941189433 is an equidigital number, since it uses as much as digits as its factorization.
469941189433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20155392, while the sum is 61.
The spelling of 469941189433 in words is "four hundred sixty-nine billion, nine hundred forty-one million, one hundred eighty-nine thousand, four hundred thirty-three".
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