Base | Representation |
---|---|
bin | 1011001110110… |
… | …0010111000001 |
3 | 10021122012120011 |
4 | 2303230113001 |
5 | 44024333343 |
6 | 4401344521 |
7 | 1111250512 |
oct | 263542701 |
9 | 107565504 |
10 | 47105473 |
11 | 24654048 |
12 | 13938141 |
13 | 99b3a7c |
14 | 6382a09 |
15 | 420729d |
hex | 2cec5c1 |
47105473 has 2 divisors, whose sum is σ = 47105474. Its totient is φ = 47105472.
The previous prime is 47105417. The next prime is 47105479. The reversal of 47105473 is 37450174.
47105473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36820624 + 10284849 = 6068^2 + 3207^2 .
It is a cyclic number.
It is not a de Polignac number, because 47105473 - 217 = 46974401 is a prime.
It is a super-3 number, since 3×471054733 (a number of 24 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (47105479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23552736 + 23552737.
It is an arithmetic number, because the mean of its divisors is an integer number (23552737).
Almost surely, 247105473 is an apocalyptic number.
It is an amenable number.
47105473 is a deficient number, since it is larger than the sum of its proper divisors (1).
47105473 is an equidigital number, since it uses as much as digits as its factorization.
47105473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11760, while the sum is 31.
The square root of 47105473 is about 6863.3426987147. The cubic root of 47105473 is about 361.1523593189.
The spelling of 47105473 in words is "forty-seven million, one hundred five thousand, four hundred seventy-three".
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