Base | Representation |
---|---|
bin | 100010010010001100110… |
… | …0011110110100100000011 |
3 | 121200110111221021021222212 |
4 | 1010210121203312210003 |
5 | 1104200143013441033 |
6 | 14004355551252335 |
7 | 664300643514665 |
oct | 104443143664403 |
9 | 17613457237885 |
10 | 4712007952643 |
11 | 1557395713872 |
12 | 641275b1a0ab |
13 | 282456c52ba4 |
14 | 1240c3332535 |
15 | 82884354748 |
hex | 449198f6903 |
4712007952643 has 2 divisors, whose sum is σ = 4712007952644. Its totient is φ = 4712007952642.
The previous prime is 4712007952577. The next prime is 4712007952657. The reversal of 4712007952643 is 3462597002174.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4712007952643 - 210 = 4712007951619 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4712007952591 and 4712007952600.
It is not a weakly prime, because it can be changed into another prime (4712007352643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2356003976321 + 2356003976322.
It is an arithmetic number, because the mean of its divisors is an integer number (2356003976322).
Almost surely, 24712007952643 is an apocalyptic number.
4712007952643 is a deficient number, since it is larger than the sum of its proper divisors (1).
4712007952643 is an equidigital number, since it uses as much as digits as its factorization.
4712007952643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 50.
The spelling of 4712007952643 in words is "four trillion, seven hundred twelve billion, seven million, nine hundred fifty-two thousand, six hundred forty-three".
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