Base | Representation |
---|---|
bin | 100010010010101011111… |
… | …0011111011111110010111 |
3 | 121200120012201111111202022 |
4 | 1010211113303323332113 |
5 | 1104204312400402003 |
6 | 14005051340403355 |
7 | 664335555015131 |
oct | 104452763737627 |
9 | 17616181444668 |
10 | 4713052356503 |
11 | 1557881205957 |
12 | 64150784655b |
13 | 28259243923a |
14 | 124181d1c051 |
15 | 828e5da7738 |
hex | 44957cfbf97 |
4713052356503 has 4 divisors (see below), whose sum is σ = 4840432149960. Its totient is φ = 4585672563048.
The previous prime is 4713052356499. The next prime is 4713052356517. The reversal of 4713052356503 is 3056532503174.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4713052356503 - 22 = 4713052356499 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4713052356563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63689896673 + ... + 63689896746.
It is an arithmetic number, because the mean of its divisors is an integer number (1210108037490).
Almost surely, 24713052356503 is an apocalyptic number.
4713052356503 is a deficient number, since it is larger than the sum of its proper divisors (127379793457).
4713052356503 is a wasteful number, since it uses less digits than its factorization.
4713052356503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127379793456.
The product of its (nonzero) digits is 1134000, while the sum is 44.
Adding to 4713052356503 its reverse (3056532503174), we get a palindrome (7769584859677).
The spelling of 4713052356503 in words is "four trillion, seven hundred thirteen billion, fifty-two million, three hundred fifty-six thousand, five hundred three".
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