Search a number
-
+
47193131651 is a prime number
BaseRepresentation
bin101011111100111011…
…100000101010000011
311111210222012111002212
4223330323200222003
51233122420203101
633402532332335
73260330000051
oct537473405203
9144728174085
1047193131651
1119018324346
129190a740ab
1345b13a9493
1423d9a3d1d1
1513632501bb
hexafcee0a83

47193131651 has 2 divisors, whose sum is σ = 47193131652. Its totient is φ = 47193131650.

The previous prime is 47193131611. The next prime is 47193131663. The reversal of 47193131651 is 15613139174.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 47193131651 - 226 = 47126022787 is a prime.

It is a super-3 number, since 3×471931316513 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 47193131599 and 47193131608.

It is not a weakly prime, because it can be changed into another prime (47193131611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23596565825 + 23596565826.

It is an arithmetic number, because the mean of its divisors is an integer number (23596565826).

Almost surely, 247193131651 is an apocalyptic number.

47193131651 is a deficient number, since it is larger than the sum of its proper divisors (1).

47193131651 is an equidigital number, since it uses as much as digits as its factorization.

47193131651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 68040, while the sum is 41.

The spelling of 47193131651 in words is "forty-seven billion, one hundred ninety-three million, one hundred thirty-one thousand, six hundred fifty-one".