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471985365073 is a prime number
BaseRepresentation
bin1101101111001001000…
…01010010000001010001
31200010021110201210202011
412313210201102001101
530213111223140243
61000454352222521
746046144260015
oct6674441220121
91603243653664
10471985365073
11172193485652
1277582b3aa41
133567b1a7911
1418bb6744545
15c42647a89d
hex6de4852051

471985365073 has 2 divisors, whose sum is σ = 471985365074. Its totient is φ = 471985365072.

The previous prime is 471985365037. The next prime is 471985365083. The reversal of 471985365073 is 370563589174.

Together with previous prime (471985365037) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 403043410449 + 68941954624 = 634857^2 + 262568^2 .

It is a cyclic number.

It is not a de Polignac number, because 471985365073 - 229 = 471448494161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 471985364999 and 471985365017.

It is not a weakly prime, because it can be changed into another prime (471985365083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235992682536 + 235992682537.

It is an arithmetic number, because the mean of its divisors is an integer number (235992682537).

Almost surely, 2471985365073 is an apocalyptic number.

It is an amenable number.

471985365073 is a deficient number, since it is larger than the sum of its proper divisors (1).

471985365073 is an equidigital number, since it uses as much as digits as its factorization.

471985365073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19051200, while the sum is 58.

The spelling of 471985365073 in words is "four hundred seventy-one billion, nine hundred eighty-five million, three hundred sixty-five thousand, seventy-three".