Base | Representation |
---|---|
bin | 10101011110000001011001… |
… | …00001101011000110001011 |
3 | 20012011022220200102212111212 |
4 | 22233000230201223012023 |
5 | 22142001141022324121 |
6 | 244224240250243335 |
7 | 12641612162605325 |
oct | 1257005441530613 |
9 | 205138820385455 |
10 | 47211027542411 |
11 | 140520a2293427 |
12 | 536599172654b |
13 | 2045c99a61085 |
14 | b930511d2615 |
15 | 56d101a7025b |
hex | 2af02c86b18b |
47211027542411 has 2 divisors, whose sum is σ = 47211027542412. Its totient is φ = 47211027542410.
The previous prime is 47211027542353. The next prime is 47211027542477. The reversal of 47211027542411 is 11424572011274.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 47211027542411 - 218 = 47211027280267 is a prime.
It is a super-2 number, since 2×472110275424112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (47211027541411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23605513771205 + 23605513771206.
It is an arithmetic number, because the mean of its divisors is an integer number (23605513771206).
Almost surely, 247211027542411 is an apocalyptic number.
47211027542411 is a deficient number, since it is larger than the sum of its proper divisors (1).
47211027542411 is an equidigital number, since it uses as much as digits as its factorization.
47211027542411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 125440, while the sum is 41.
Adding to 47211027542411 its reverse (11424572011274), we get a palindrome (58635599553685).
The spelling of 47211027542411 in words is "forty-seven trillion, two hundred eleven billion, twenty-seven million, five hundred forty-two thousand, four hundred eleven".
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