Base | Representation |
---|---|
bin | 10101011110000001011001… |
… | …01100110100101100101011 |
3 | 20012011022220212221100222212 |
4 | 22233000230230310230223 |
5 | 22142001142244342243 |
6 | 244224240433035335 |
7 | 12641612226501044 |
oct | 1257005454645453 |
9 | 205138825840885 |
10 | 47211030465323 |
11 | 140520a39aa45a |
12 | 53659926b5b4b |
13 | 2045c9a5455ca |
14 | b930517538cb |
15 | 56d101e4b318 |
hex | 2af02cb34b2b |
47211030465323 has 2 divisors, whose sum is σ = 47211030465324. Its totient is φ = 47211030465322.
The previous prime is 47211030465211. The next prime is 47211030465349. The reversal of 47211030465323 is 32356403011274.
47211030465323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 47211030465323 - 212 = 47211030461227 is a prime.
It is not a weakly prime, because it can be changed into another prime (47211030465373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23605515232661 + 23605515232662.
It is an arithmetic number, because the mean of its divisors is an integer number (23605515232662).
Almost surely, 247211030465323 is an apocalyptic number.
47211030465323 is a deficient number, since it is larger than the sum of its proper divisors (1).
47211030465323 is an equidigital number, since it uses as much as digits as its factorization.
47211030465323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 41.
Adding to 47211030465323 its reverse (32356403011274), we get a palindrome (79567433476597).
The spelling of 47211030465323 in words is "forty-seven trillion, two hundred eleven billion, thirty million, four hundred sixty-five thousand, three hundred twenty-three".
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