Base | Representation |
---|---|
bin | 101011111111110011… |
… | …010110110000100011 |
3 | 11111221022212222210001 |
4 | 223333303112300203 |
5 | 1233222234404403 |
6 | 33411413320431 |
7 | 3261453433153 |
oct | 537763266043 |
9 | 144838788701 |
10 | 47241325603 |
11 | 1904255115a |
12 | 91a5036117 |
13 | 45bb381804 |
14 | 24021c6763 |
15 | 13675bec1d |
hex | affcd6c23 |
47241325603 has 2 divisors, whose sum is σ = 47241325604. Its totient is φ = 47241325602.
The previous prime is 47241325561. The next prime is 47241325609. The reversal of 47241325603 is 30652314274.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47241325603 is a prime.
It is not a weakly prime, because it can be changed into another prime (47241325609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23620662801 + 23620662802.
It is an arithmetic number, because the mean of its divisors is an integer number (23620662802).
Almost surely, 247241325603 is an apocalyptic number.
47241325603 is a deficient number, since it is larger than the sum of its proper divisors (1).
47241325603 is an equidigital number, since it uses as much as digits as its factorization.
47241325603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 37.
Adding to 47241325603 its reverse (30652314274), we get a palindrome (77893639877).
The spelling of 47241325603 in words is "forty-seven billion, two hundred forty-one million, three hundred twenty-five thousand, six hundred three".
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