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47284019365409 is a prime number
BaseRepresentation
bin10101100000001001010110…
…01011011000011000100001
320012102022022121102122222122
422300010223023120120201
522144200132424143114
6244321551214314025
712650105036063111
oct1260045313303041
9205368277378878
1047284019365409
1114080049270392
125377b624b8915
13204cb2cc89098
14b967b72c3041
1556ee74b5be8e
hex2b012b2d8621

47284019365409 has 2 divisors, whose sum is σ = 47284019365410. Its totient is φ = 47284019365408.

The previous prime is 47284019365381. The next prime is 47284019365447. The reversal of 47284019365409 is 90456391048274.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46027703434384 + 1256315931025 = 6784372^2 + 1120855^2 .

It is a cyclic number.

It is not a de Polignac number, because 47284019365409 - 232 = 47279724398113 is a prime.

It is a super-4 number, since 4×472840193654094 (a number of 56 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (47284019325409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23642009682704 + 23642009682705.

It is an arithmetic number, because the mean of its divisors is an integer number (23642009682705).

It is a 1-persistent number, because it is pandigital, but 2⋅47284019365409 = 94568038730818 is not.

Almost surely, 247284019365409 is an apocalyptic number.

It is an amenable number.

47284019365409 is a deficient number, since it is larger than the sum of its proper divisors (1).

47284019365409 is an equidigital number, since it uses as much as digits as its factorization.

47284019365409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52254720, while the sum is 62.

The spelling of 47284019365409 in words is "forty-seven trillion, two hundred eighty-four billion, nineteen million, three hundred sixty-five thousand, four hundred nine".