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47321354035211 is a prime number
BaseRepresentation
bin10101100001001110111000…
…11111110110000000001011
320012112212200112012101210212
422300213130133312000023
522200303113113111321
6244351044022031335
712652566160405664
oct1260473437660013
9205485615171725
1047321354035211
11140949677623a3
12538324187854b
1320534ccaa3589
14b985198c436b
15570e0c65b55b
hex2b09dc7f600b

47321354035211 has 2 divisors, whose sum is σ = 47321354035212. Its totient is φ = 47321354035210.

The previous prime is 47321354035169. The next prime is 47321354035271. The reversal of 47321354035211 is 11253045312374.

47321354035211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 47321354035211 - 210 = 47321354034187 is a prime.

It is not a weakly prime, because it can be changed into another prime (47321354035271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23660677017605 + 23660677017606.

It is an arithmetic number, because the mean of its divisors is an integer number (23660677017606).

Almost surely, 247321354035211 is an apocalyptic number.

47321354035211 is a deficient number, since it is larger than the sum of its proper divisors (1).

47321354035211 is an equidigital number, since it uses as much as digits as its factorization.

47321354035211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 41.

Adding to 47321354035211 its reverse (11253045312374), we get a palindrome (58574399347585).

The spelling of 47321354035211 in words is "forty-seven trillion, three hundred twenty-one billion, three hundred fifty-four million, thirty-five thousand, two hundred eleven".