Base | Representation |
---|---|
bin | 100010100000010101001… |
… | …0111111101010011101011 |
3 | 121210100211212020210120112 |
4 | 1011000222113331103223 |
5 | 1110144320313141113 |
6 | 14030335134044535 |
7 | 666423654564635 |
oct | 105005227752353 |
9 | 17710755223515 |
10 | 4742354818283 |
11 | 1569248731115 |
12 | 64712504974b |
13 | 285282144614 |
14 | 12576186da55 |
15 | 8355d6485a8 |
hex | 4502a5fd4eb |
4742354818283 has 2 divisors, whose sum is σ = 4742354818284. Its totient is φ = 4742354818282.
The previous prime is 4742354818273. The next prime is 4742354818373. The reversal of 4742354818283 is 3828184532474.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4742354818283 - 216 = 4742354752747 is a prime.
It is a super-3 number, since 3×47423548182833 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4742354818213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2371177409141 + 2371177409142.
It is an arithmetic number, because the mean of its divisors is an integer number (2371177409142).
Almost surely, 24742354818283 is an apocalyptic number.
4742354818283 is a deficient number, since it is larger than the sum of its proper divisors (1).
4742354818283 is an equidigital number, since it uses as much as digits as its factorization.
4742354818283 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41287680, while the sum is 59.
The spelling of 4742354818283 in words is "four trillion, seven hundred forty-two billion, three hundred fifty-four million, eight hundred eighteen thousand, two hundred eighty-three".
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