Base | Representation |
---|---|
bin | 101100001100001111… |
… | …011011011010110001 |
3 | 11112110212120022202102 |
4 | 230030033123122301 |
5 | 1234134200330223 |
6 | 33444230230145 |
7 | 3266566304255 |
oct | 541417333261 |
9 | 145425508672 |
10 | 47450011313 |
11 | 1913a326891 |
12 | 9242ab5355 |
13 | 462268a393 |
14 | 2421bca265 |
15 | 137aa92928 |
hex | b0c3db6b1 |
47450011313 has 2 divisors, whose sum is σ = 47450011314. Its totient is φ = 47450011312.
The previous prime is 47450011307. The next prime is 47450011339. The reversal of 47450011313 is 31311005474.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33048331264 + 14401680049 = 181792^2 + 120007^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47450011313 is a prime.
It is not a weakly prime, because it can be changed into another prime (47450011813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23725005656 + 23725005657.
It is an arithmetic number, because the mean of its divisors is an integer number (23725005657).
Almost surely, 247450011313 is an apocalyptic number.
It is an amenable number.
47450011313 is a deficient number, since it is larger than the sum of its proper divisors (1).
47450011313 is an equidigital number, since it uses as much as digits as its factorization.
47450011313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 47450011313 its reverse (31311005474), we get a palindrome (78761016787).
The spelling of 47450011313 in words is "forty-seven billion, four hundred fifty million, eleven thousand, three hundred thirteen".
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