Base | Representation |
---|---|
bin | 101100001110000101… |
… | …110000010101111011 |
3 | 11112120000221020102002 |
4 | 230032011300111323 |
5 | 1234220120430021 |
6 | 33451255131215 |
7 | 3300424044632 |
oct | 541605602573 |
9 | 145500836362 |
10 | 47481030011 |
11 | 19155892678 |
12 | 9251373b0b |
13 | 4628c2ac3c |
14 | 2425d82519 |
15 | 137d66d50b |
hex | b0e17057b |
47481030011 has 2 divisors, whose sum is σ = 47481030012. Its totient is φ = 47481030010.
The previous prime is 47481029989. The next prime is 47481030067. The reversal of 47481030011 is 11003018474.
47481030011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47481030011 is a prime.
It is not a weakly prime, because it can be changed into another prime (47481033011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23740515005 + 23740515006.
It is an arithmetic number, because the mean of its divisors is an integer number (23740515006).
Almost surely, 247481030011 is an apocalyptic number.
47481030011 is a deficient number, since it is larger than the sum of its proper divisors (1).
47481030011 is an equidigital number, since it uses as much as digits as its factorization.
47481030011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 47481030011 its reverse (11003018474), we get a palindrome (58484048485).
The spelling of 47481030011 in words is "forty-seven billion, four hundred eighty-one million, thirty thousand, eleven".
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