Base | Representation |
---|---|
bin | 1011011001111… |
… | …0010000000001 |
3 | 10100000020001211 |
4 | 2312132100001 |
5 | 44221142423 |
6 | 4425130121 |
7 | 1120404025 |
oct | 266362001 |
9 | 110006054 |
10 | 47834113 |
11 | 25001528 |
12 | 14029941 |
13 | 9baa612 |
14 | 64d2385 |
15 | 42ed10d |
hex | 2d9e401 |
47834113 has 2 divisors, whose sum is σ = 47834114. Its totient is φ = 47834112.
The previous prime is 47834099. The next prime is 47834131. The reversal of 47834113 is 31143874.
Together with next prime (47834131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47238129 + 595984 = 6873^2 + 772^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47834113 is a prime.
It is not a weakly prime, because it can be changed into another prime (47834173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23917056 + 23917057.
It is an arithmetic number, because the mean of its divisors is an integer number (23917057).
Almost surely, 247834113 is an apocalyptic number.
It is an amenable number.
47834113 is a deficient number, since it is larger than the sum of its proper divisors (1).
47834113 is an equidigital number, since it uses as much as digits as its factorization.
47834113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8064, while the sum is 31.
The square root of 47834113 is about 6916.2210057227. The cubic root of 47834113 is about 363.0049732817.
Adding to 47834113 its reverse (31143874), we get a palindrome (78977987).
The spelling of 47834113 in words is "forty-seven million, eight hundred thirty-four thousand, one hundred thirteen".
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