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47913476857 is a prime number
BaseRepresentation
bin101100100111110111…
…011010001011111001
311120200011122210221221
4230213313122023321
51241111322224412
634002224032041
73314224555621
oct544767321371
9146604583857
1047913476857
11193579aa364
129352162621
1346976c014c
142467591881
1513a65e0b07
hexb27dda2f9

47913476857 has 2 divisors, whose sum is σ = 47913476858. Its totient is φ = 47913476856.

The previous prime is 47913476851. The next prime is 47913476869. The reversal of 47913476857 is 75867431974.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31420753081 + 16492723776 = 177259^2 + 128424^2 .

It is a cyclic number.

It is not a de Polignac number, because 47913476857 - 211 = 47913474809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 47913476795 and 47913476804.

It is not a weakly prime, because it can be changed into another prime (47913476851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23956738428 + 23956738429.

It is an arithmetic number, because the mean of its divisors is an integer number (23956738429).

Almost surely, 247913476857 is an apocalyptic number.

It is an amenable number.

47913476857 is a deficient number, since it is larger than the sum of its proper divisors (1).

47913476857 is an equidigital number, since it uses as much as digits as its factorization.

47913476857 is an evil number, because the sum of its binary digits is even.

The product of its digits is 35562240, while the sum is 61.

The spelling of 47913476857 in words is "forty-seven billion, nine hundred thirteen million, four hundred seventy-six thousand, eight hundred fifty-seven".