Base | Representation |
---|---|
bin | 101100101001100111… |
… | …001101100001011001 |
3 | 11120202012210211022220 |
4 | 230221213031201121 |
5 | 1241141323110423 |
6 | 34005152134253 |
7 | 3315031643466 |
oct | 545147154131 |
9 | 146665724286 |
10 | 47942785113 |
11 | 193724a8063 |
12 | 935bb37389 |
13 | 46a07b2302 |
14 | 246b42066d |
15 | 13a8e7e9e3 |
hex | b299cd859 |
47942785113 has 32 divisors (see below), whose sum is σ = 68098901376. Its totient is φ = 29958501888.
The previous prime is 47942785049. The next prime is 47942785133. The reversal of 47942785113 is 31158724974.
47942785113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 47942785113 - 26 = 47942785049 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (47942785133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 279631 + ... + 417227.
It is an arithmetic number, because the mean of its divisors is an integer number (2128090668).
Almost surely, 247942785113 is an apocalyptic number.
47942785113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
47942785113 is a deficient number, since it is larger than the sum of its proper divisors (20156116263).
47942785113 is a wasteful number, since it uses less digits than its factorization.
47942785113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137753.
The product of its digits is 1693440, while the sum is 51.
The spelling of 47942785113 in words is "forty-seven billion, nine hundred forty-two million, seven hundred eighty-five thousand, one hundred thirteen".
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