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481029953 is a prime number
BaseRepresentation
bin11100101010111…
…110111101000001
31020112010212001012
4130222332331001
51441120424303
6115422050305
714630454455
oct3452767501
91215125035
10481029953
1122758aa18
12115119995
1378872711
1447c58665
152c36c5d8
hex1cabef41

481029953 has 2 divisors, whose sum is σ = 481029954. Its totient is φ = 481029952.

The previous prime is 481029937. The next prime is 481030013. The reversal of 481029953 is 359920184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 322849024 + 158180929 = 17968^2 + 12577^2 .

It is a cyclic number.

It is not a de Polignac number, because 481029953 - 24 = 481029937 is a prime.

It is a super-3 number, since 3×4810299533 (a number of 27 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 481029953.

It is not a weakly prime, because it can be changed into another prime (481022953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240514976 + 240514977.

It is an arithmetic number, because the mean of its divisors is an integer number (240514977).

Almost surely, 2481029953 is an apocalyptic number.

It is an amenable number.

481029953 is a deficient number, since it is larger than the sum of its proper divisors (1).

481029953 is an equidigital number, since it uses as much as digits as its factorization.

481029953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 41.

The square root of 481029953 is about 21932.3950584518. The cubic root of 481029953 is about 783.5331461704.

The spelling of 481029953 in words is "four hundred eighty-one million, twenty-nine thousand, nine hundred fifty-three".