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48105401 is a prime number
BaseRepresentation
bin1011011110000…
…0011110111001
310100112000012112
42313200132321
544303333101
64435022105
71122613661
oct267403671
9110460175
1048105401
1125177333
121413a935
139c73c46
1465631a1
1543536bb
hex2de07b9

48105401 has 2 divisors, whose sum is σ = 48105402. Its totient is φ = 48105400.

The previous prime is 48105383. The next prime is 48105469. The reversal of 48105401 is 10450184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33051001 + 15054400 = 5749^2 + 3880^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-48105401 is a prime.

It is a super-3 number, since 3×481054013 (a number of 24 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (48105901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24052700 + 24052701.

It is an arithmetic number, because the mean of its divisors is an integer number (24052701).

Almost surely, 248105401 is an apocalyptic number.

It is an amenable number.

48105401 is a deficient number, since it is larger than the sum of its proper divisors (1).

48105401 is an equidigital number, since it uses as much as digits as its factorization.

48105401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 640, while the sum is 23.

The square root of 48105401 is about 6935.8057210392. The cubic root of 48105401 is about 363.6899328864.

Adding to 48105401 its reverse (10450184), we get a palindrome (58555585).

The spelling of 48105401 in words is "forty-eight million, one hundred five thousand, four hundred one".