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48110404801 is a prime number
BaseRepresentation
bin101100110011100110…
…101000010011000001
311121011220012210022111
4230303212220103001
51242012230423201
634033540535321
73322135456564
oct546346502301
9147156183274
1048110404801
1119449084228
1293a80b1541
1346c9440064
1424857b44db
1513b8a3eb51
hexb339a84c1

48110404801 has 2 divisors, whose sum is σ = 48110404802. Its totient is φ = 48110404800.

The previous prime is 48110404777. The next prime is 48110404817. The reversal of 48110404801 is 10840401184.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36510037776 + 11600367025 = 191076^2 + 107705^2 .

It is a cyclic number.

It is not a de Polignac number, because 48110404801 - 215 = 48110372033 is a prime.

It is a super-2 number, since 2×481104048012 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (48110404831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24055202400 + 24055202401.

It is an arithmetic number, because the mean of its divisors is an integer number (24055202401).

Almost surely, 248110404801 is an apocalyptic number.

It is an amenable number.

48110404801 is a deficient number, since it is larger than the sum of its proper divisors (1).

48110404801 is an equidigital number, since it uses as much as digits as its factorization.

48110404801 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4096, while the sum is 31.

Adding to 48110404801 its reverse (10840401184), we get a palindrome (58950805985).

The spelling of 48110404801 in words is "forty-eight billion, one hundred ten million, four hundred four thousand, eight hundred one".