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481143307 is a prime number
BaseRepresentation
bin11100101011011…
…010101000001011
31020112100121112111
4130223122220023
51441133041212
6115424323151
714631436111
oct3453325013
91215317474
10481143307
112276580a7
121151734b7
13788b21a8
1447c87ab1
152c390ea7
hex1cadaa0b

481143307 has 2 divisors, whose sum is σ = 481143308. Its totient is φ = 481143306.

The previous prime is 481143283. The next prime is 481143329. The reversal of 481143307 is 703341184.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-481143307 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (481143347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240571653 + 240571654.

It is an arithmetic number, because the mean of its divisors is an integer number (240571654).

Almost surely, 2481143307 is an apocalyptic number.

481143307 is a deficient number, since it is larger than the sum of its proper divisors (1).

481143307 is an equidigital number, since it uses as much as digits as its factorization.

481143307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

The square root of 481143307 is about 21934.9790745284. The cubic root of 481143307 is about 783.5946874806.

The spelling of 481143307 in words is "four hundred eighty-one million, one hundred forty-three thousand, three hundred seven".