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481245113 is a prime number
BaseRepresentation
bin11100101011110…
…011011110111001
31020112112210012002
4130223303132321
51441144320423
6115430430345
714632341656
oct3453633671
91215483162
10481245113
11227717638
121152023b5
137891962b
1447cb2c2d
152c3b1228
hex1caf37b9

481245113 has 2 divisors, whose sum is σ = 481245114. Its totient is φ = 481245112.

The previous prime is 481245097. The next prime is 481245139. The reversal of 481245113 is 311542184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 369139369 + 112105744 = 19213^2 + 10588^2 .

It is a cyclic number.

It is not a de Polignac number, because 481245113 - 24 = 481245097 is a prime.

It is not a weakly prime, because it can be changed into another prime (481245143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240622556 + 240622557.

It is an arithmetic number, because the mean of its divisors is an integer number (240622557).

Almost surely, 2481245113 is an apocalyptic number.

It is an amenable number.

481245113 is a deficient number, since it is larger than the sum of its proper divisors (1).

481245113 is an equidigital number, since it uses as much as digits as its factorization.

481245113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3840, while the sum is 29.

The square root of 481245113 is about 21937.2995831301. The cubic root of 481245113 is about 783.6499509982.

Adding to 481245113 its reverse (311542184), we get a palindrome (792787297).

The spelling of 481245113 in words is "four hundred eighty-one million, two hundred forty-five thousand, one hundred thirteen".