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4814331326641 is a prime number
BaseRepresentation
bin100011000001110110010…
…0000100011000010110001
3122001020122000202021012101
41012003230200203002301
51112334222304423031
614123401232300401
71004552422035424
oct106035440430261
918036560667171
104814331326641
111596823585171
126590719a1701
1328bcb2bcc835
1412902cb879bb
158537252b361
hex460ec8230b1

4814331326641 has 2 divisors, whose sum is σ = 4814331326642. Its totient is φ = 4814331326640.

The previous prime is 4814331326617. The next prime is 4814331326683. The reversal of 4814331326641 is 1466231334184.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4574020580416 + 240310746225 = 2138696^2 + 490215^2 .

It is a cyclic number.

It is not a de Polignac number, because 4814331326641 - 27 = 4814331326513 is a prime.

It is a super-2 number, since 2×48143313266412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4814331326591 and 4814331326600.

It is not a weakly prime, because it can be changed into another prime (4814331320641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2407165663320 + 2407165663321.

It is an arithmetic number, because the mean of its divisors is an integer number (2407165663321).

Almost surely, 24814331326641 is an apocalyptic number.

It is an amenable number.

4814331326641 is a deficient number, since it is larger than the sum of its proper divisors (1).

4814331326641 is an equidigital number, since it uses as much as digits as its factorization.

4814331326641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 995328, while the sum is 46.

The spelling of 4814331326641 in words is "four trillion, eight hundred fourteen billion, three hundred thirty-one million, three hundred twenty-six thousand, six hundred forty-one".