Base | Representation |
---|---|
bin | 100011000001110110010… |
… | …0000101111010000000001 |
3 | 122001020122000211210210020 |
4 | 1012003230200233100001 |
5 | 1112334222313023031 |
6 | 14123401233324053 |
7 | 1004552422334253 |
oct | 106035440572001 |
9 | 18036560753706 |
10 | 4814331376641 |
11 | 1596823609796 |
12 | 659071a06629 |
13 | 28bcb2c19517 |
14 | 12902cb9bcd3 |
15 | 8537253b096 |
hex | 460ec82f401 |
4814331376641 has 16 divisors (see below), whose sum is σ = 6456746390400. Its totient is φ = 3190784380928.
The previous prime is 4814331376637. The next prime is 4814331376717. The reversal of 4814331376641 is 1466731334184.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 4814331376641 - 22 = 4814331376637 is a prime.
It is a super-2 number, since 2×48143313766412 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4814331326641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5741421 + ... + 6526298.
It is an arithmetic number, because the mean of its divisors is an integer number (403546649400).
Almost surely, 24814331376641 is an apocalyptic number.
It is an amenable number.
4814331376641 is a deficient number, since it is larger than the sum of its proper divisors (1642415013759).
4814331376641 is a wasteful number, since it uses less digits than its factorization.
4814331376641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12268488.
The product of its digits is 3483648, while the sum is 51.
The spelling of 4814331376641 in words is "four trillion, eight hundred fourteen billion, three hundred thirty-one million, three hundred seventy-six thousand, six hundred forty-one".
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