Base | Representation |
---|---|
bin | 1000111101111101… |
… | …00101010111011001 |
3 | 110102112200120200201 |
4 | 10132332211113121 |
5 | 34330030033003 |
6 | 2113431302201 |
7 | 230212121236 |
oct | 43676452731 |
9 | 13375616621 |
10 | 4814689753 |
11 | 2050848745 |
12 | b2451a961 |
13 | 5b9648963 |
14 | 33962478d |
15 | 1d2a4eb1d |
hex | 11efa55d9 |
4814689753 has 2 divisors, whose sum is σ = 4814689754. Its totient is φ = 4814689752.
The previous prime is 4814689741. The next prime is 4814689757. The reversal of 4814689753 is 3579864184.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3564925849 + 1249763904 = 59707^2 + 35352^2 .
It is a cyclic number.
It is not a de Polignac number, because 4814689753 - 25 = 4814689721 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4814689694 and 4814689703.
It is not a weakly prime, because it can be changed into another prime (4814689757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2407344876 + 2407344877.
It is an arithmetic number, because the mean of its divisors is an integer number (2407344877).
Almost surely, 24814689753 is an apocalyptic number.
It is an amenable number.
4814689753 is a deficient number, since it is larger than the sum of its proper divisors (1).
4814689753 is an equidigital number, since it uses as much as digits as its factorization.
4814689753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5806080, while the sum is 55.
The square root of 4814689753 is about 69387.9654767309. The cubic root of 4814689753 is about 1688.5843861380.
The spelling of 4814689753 in words is "four billion, eight hundred fourteen million, six hundred eighty-nine thousand, seven hundred fifty-three".
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