483111135 has 80 divisors (see below), whose sum is σ = 944032320. Its totient is φ = 234938880.

The previous prime is 483111133. The next prime is 483111143. The reversal of 483111135 is 531111384.

It is not a de Polignac number, because 483111135 - 2¹ = 483111133 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 483111099 and 483111108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (483111131) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 468070 + ... + 469100.

It is an arithmetic number, because the mean of its divisors is an integer number (11800404).

Almost surely, 2^483111135 is an apocalyptic number.

483111135 is a gapful number since it is divisible by the number (45) formed by its first and last digit.

483111135 is a deficient number, since it is larger than the sum of its proper divisors (460921185).

483111135 is a wasteful number, since it uses less digits than its factorization.

483111135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1150 (or 1141 counting only the distinct ones).

The product of its digits is 1440, while the sum is 27.

The square root of 483111135 is about 21979.7892392079. The cubic root of 483111135 is about 784.6615090332.

The spelling of 483111135 in words is "four hundred eighty-three million, one hundred eleven thousand, one hundred thirty-five".