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483142894080 = 29357112172257
BaseRepresentation
bin1110000011111011000…
…11111000001000000000
31201012002001121000011020
413001331203320020000
530403434040102310
61005541444545440
746622505561060
oct7017543701000
91635061530136
10483142894080
11176999628300
12797776b2280
13367389390a2
14195544dd3a0
15c87ac85170
hex707d8f8200

483142894080 has 1440 divisors, whose sum is σ = 2069124317568. Its totient is φ = 94120181760.

The previous prime is 483142894079. The next prime is 483142894103. The reversal of 483142894080 is 80498241384.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1879933312 + ... + 1879933568.

Almost surely, 2483142894080 is an apocalyptic number.

483142894080 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 483142894080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1034562158784).

483142894080 is an abundant number, since it is smaller than the sum of its proper divisors (1585981423488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

483142894080 is a wasteful number, since it uses less digits than its factorization.

483142894080 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 346 (or 302 counting only the distinct ones).

The product of its (nonzero) digits is 1769472, while the sum is 51.

The spelling of 483142894080 in words is "four hundred eighty-three billion, one hundred forty-two million, eight hundred ninety-four thousand, eighty".