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4831738853761 = 5147938748563
BaseRepresentation
bin100011001001111101000…
…0100111111100110000001
3122002220120012002021020001
41012103322010333212001
51113130400121310021
614135400432120001
71006036664421361
oct106237204774601
918086505067201
104831738853761
1115a314668aa16
1266050b696001
1329082846b641
14129c00a2a9a1
1585a408a2091
hex464fa13f981

4831738853761 has 4 divisors (see below), whose sum is σ = 4832677607472. Its totient is φ = 4830800100052.

The previous prime is 4831738853737. The next prime is 4831738853783. The reversal of 4831738853761 is 1673588371384.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4831738853761 - 213 = 4831738845569 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4831738853693 and 4831738853702.

It is not an unprimeable number, because it can be changed into a prime (4831738853731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469369135 + ... + 469379428.

It is an arithmetic number, because the mean of its divisors is an integer number (1208169401868).

Almost surely, 24831738853761 is an apocalyptic number.

It is an amenable number.

4831738853761 is a deficient number, since it is larger than the sum of its proper divisors (938753711).

4831738853761 is an equidigital number, since it uses as much as digits as its factorization.

4831738853761 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 938753710.

The product of its digits is 81285120, while the sum is 64.

The spelling of 4831738853761 in words is "four trillion, eight hundred thirty-one billion, seven hundred thirty-eight million, eight hundred fifty-three thousand, seven hundred sixty-one".

Divisors: 1 5147 938748563 4831738853761