Base | Representation |
---|---|
bin | 101101000001001110… |
… | …010010011001111101 |
3 | 11121202211011210020202 |
4 | 231001032102121331 |
5 | 1242444224422301 |
6 | 34112342253245 |
7 | 3330611624213 |
oct | 550116223175 |
9 | 147684153222 |
10 | 48338904701 |
11 | 1955606261a |
12 | 9450727225 |
13 | 47348955b9 |
14 | 24a7c94cb3 |
15 | 13cdb2866b |
hex | b4139267d |
48338904701 has 4 divisors (see below), whose sum is σ = 50883057600. Its totient is φ = 45794751804.
The previous prime is 48338904689. The next prime is 48338904709. The reversal of 48338904701 is 10740983384.
48338904701 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 48338904701 - 210 = 48338903677 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (48338904709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1272076421 + ... + 1272076458.
It is an arithmetic number, because the mean of its divisors is an integer number (12720764400).
Almost surely, 248338904701 is an apocalyptic number.
It is an amenable number.
48338904701 is a deficient number, since it is larger than the sum of its proper divisors (2544152899).
48338904701 is a wasteful number, since it uses less digits than its factorization.
48338904701 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2544152898.
The product of its (nonzero) digits is 580608, while the sum is 47.
The spelling of 48338904701 in words is "forty-eight billion, three hundred thirty-eight million, nine hundred four thousand, seven hundred one".
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