Base | Representation |
---|---|
bin | 1110000100011110000… |
… | …10110100111011100011 |
3 | 1201012211111112111212001 |
4 | 13002033002310323203 |
5 | 30410034133021011 |
6 | 1010030523544431 |
7 | 46633000033054 |
oct | 7021702647343 |
9 | 1635744474761 |
10 | 483436220131 |
11 | 17702a163527 |
12 | 7983998b117 |
13 | 3678463b1b7 |
14 | 1958145672b |
15 | c8968c67c1 |
hex | 708f0b4ee3 |
483436220131 has 2 divisors, whose sum is σ = 483436220132. Its totient is φ = 483436220130.
The previous prime is 483436220117. The next prime is 483436220167. The reversal of 483436220131 is 131022634384.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 483436220131 - 213 = 483436211939 is a prime.
It is a super-2 number, since 2×4834362201312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (483436220171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241718110065 + 241718110066.
It is an arithmetic number, because the mean of its divisors is an integer number (241718110066).
Almost surely, 2483436220131 is an apocalyptic number.
483436220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
483436220131 is an equidigital number, since it uses as much as digits as its factorization.
483436220131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 37.
The spelling of 483436220131 in words is "four hundred eighty-three billion, four hundred thirty-six million, two hundred twenty thousand, one hundred thirty-one".
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