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48346231657 is a prime number
BaseRepresentation
bin101101000001101010…
…001111001101101001
311121210022222000221111
4231001222033031221
51243003113403112
634113203310321
73331031121463
oct550152171551
9147708860844
1048346231657
111955a207459
12945307b3a1
13473625c589
1424a8c41133
1513ce5c45a7
hexb41a8f369

48346231657 has 2 divisors, whose sum is σ = 48346231658. Its totient is φ = 48346231656.

The previous prime is 48346231613. The next prime is 48346231663. The reversal of 48346231657 is 75613264384.

48346231657 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45194082921 + 3152148736 = 212589^2 + 56144^2 .

It is a cyclic number.

It is not a de Polignac number, because 48346231657 - 231 = 46198748009 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 48346231657.

It is not a weakly prime, because it can be changed into another prime (48346231607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24173115828 + 24173115829.

It is an arithmetic number, because the mean of its divisors is an integer number (24173115829).

Almost surely, 248346231657 is an apocalyptic number.

It is an amenable number.

48346231657 is a deficient number, since it is larger than the sum of its proper divisors (1).

48346231657 is an equidigital number, since it uses as much as digits as its factorization.

48346231657 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2903040, while the sum is 49.

The spelling of 48346231657 in words is "forty-eight billion, three hundred forty-six million, two hundred thirty-one thousand, six hundred fifty-seven".