Base | Representation |
---|---|
bin | 1110000100100001101… |
… | …01101001011001010011 |
3 | 1201012220121011201100101 |
4 | 13002100311221121103 |
5 | 30410114334210233 |
6 | 1010033521033231 |
7 | 46633513624132 |
oct | 7022065513123 |
9 | 1635817151311 |
10 | 483466319443 |
11 | 177045151598 |
12 | 79847a85817 |
13 | 3678a949443 |
14 | 1958544d919 |
15 | c89936ec7d |
hex | 7090d69653 |
483466319443 has 2 divisors, whose sum is σ = 483466319444. Its totient is φ = 483466319442.
The previous prime is 483466319417. The next prime is 483466319449. The reversal of 483466319443 is 344913664384.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-483466319443 is a prime.
It is not a weakly prime, because it can be changed into another prime (483466319449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 241733159721 + 241733159722.
It is an arithmetic number, because the mean of its divisors is an integer number (241733159722).
Almost surely, 2483466319443 is an apocalyptic number.
483466319443 is a deficient number, since it is larger than the sum of its proper divisors (1).
483466319443 is an equidigital number, since it uses as much as digits as its factorization.
483466319443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17915904, while the sum is 55.
The spelling of 483466319443 in words is "four hundred eighty-three billion, four hundred sixty-six million, three hundred nineteen thousand, four hundred forty-three".
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